개발자 톡
C초보가 복잡하게 푼 C언어 코드 공유합니다.. 간단하게 할 방법 있으면 공유해쥬세요,,
- 등록일
- 2024-03-16 15:17:55
- 조회수
- 528
- 작성자
- yeinseo1142
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int one[3]={0,0,0},two[3]={0,0,0},three[3]={0,0,0};
int num[3]={0,0,0};
int min=0;
scanf("%d %d %d",&one[0],&one[1],&one[2]);
scanf("%d %d %d",&two[0],&two[1],&two[2]);
scanf("%d %d %d",&three[0],&three[1],&three[2]);
for(int i=0;i<3;i++){
if (one[i]==two[i]&&two[i]==three[i]&&one[i]==three[i]){
num[i]=0;
}
else{
int a=one[i],b=two[i],c=three[i];
if(a!=c)num[i] = abs(a - b) + abs(b - c);
else num[i] = abs(a-b);
}
}
for(int i=0;i<2;i++){
if(num[i]<=num[i+1]) min=num[i];
else min=num[i+1];
}
if (num[2]<num[0]) min=num[2];
else min=num[0];
if (one[0]==one[1]&&one[1]==one[2]) num[0]=0;
else{
int a=one[0],b=one[1],c=one[2];
if(a!=c)num[0] = abs(a - b) + abs(b - c);
else num[0] = abs(a-b);
}
if (two[0]==two[1]&&two[1]==two[2]) num[1]=0;
else{
int a=two[0],b=two[1],c=two[2];
if(a!=c)num[1] = abs(a - b) + abs(b - c);
else num[1] = abs(a-b);
}
if (three[0]==three[1]&&three[1]==three[2]) num[2]=0;
else{
int a=three[0],b=three[1],c=three[2];
if(a!=c)num[2] = abs(a - b) + abs(b - c);
else num[2] = abs(a-b);
}
for(int i=0;i<2;i++){
if(num[i]<num[i+1]&&min>num[i]) min=num[i];
else if(min>num[i+1]) min=num[i+1];
}
printf("%d",min);
return 0;
}